Android Intent Question

i make a app with webview.

Can i open URL Like

intent://view?id=123#Intent;package=app.another.id;scheme=another;launchFlags=268435456;end;

with Titanium.Platform.openURL?

there was occur "not found error"

how can i open app with this uri in titanium?

intent://view?id=123#Intent;package=app.another.id;scheme=another;launchFlags=268435456;end;

i found this code for android

Intent i = Intent.parseUri(url, Intent.URI_INTENT_SCHEME);
startActivity(i);